one + then one -, it repeats forever, so (-1)^(r+1)
when r=1, “+”
when r=2, “-”
when r=3. “+” and so on. The denominator is odd number i.e. 2r-1
so summation from 1 to n for (-1)^(r+1)/(2r-1)
teacher 2c question 7 how to do ???
2c??? Is it 4c Q7?
4c Q7 is 2 GPs using sum of GP. Solved!
4c haha type wrong~~ I knew how to solve already thank you teacher
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