首先聪明和敏捷对于数学学习来说固然重要，但良好的学习方法可以把学习效果提高几倍，这是先天因素不可比拟的。学好数学首先要过的是心理关。任何事情都有一个由量变到质变的循序渐进的积累过程。

一．预习。不等于浏览。要深入了解知识内容，找出重点，难点，疑点，经过思考，标出不懂的，有益于听课抓住重点，还可以培养自学能力，有时间还可以超前学习。

二．听讲。核心在课堂。1。以听为主，兼顾记录。2。注重过程，轻结论。

3．有重点。4。提高听课效率。

三．复习。像演电影一样把课堂复习，整理笔记，

四．多做练习。1。晚上吃饭后，坐到书桌时，看数学最适合，2。做一道数学题，每一步都要多问个别为什么，不能只满足于老师课堂上的灌输式传授和书本上的简单讲述，要想提高必须要一步一步推，一步一步想，每个过程都必不可少，3。不要粗心大意，4。做完每一道题，要想想为什么会想到这样做，大脑建立一种条件发射，关键在于每做一道题要从中得到东西，错在哪，5。解题都有固定的套路。6还有大胆的夸奖自己，那是树立信心的关键时刻，

五．总结。1。要将所学的知识变成知识网，从大主干到分枝，清晰地深存在脑中，新题想到老题，从而一通百通。2。建立错误集，错误多半会错上两次，在有意识改正的情况下，还有可能错下去，最有效的应该是会正确地做这道题，并在下次遇到同样情况时候有注意的意识。3。周末再将一周做的题回头看一番，提出每道题的思路方法。4有问题一定要问。

六．考前复习，1。前2周就要开始复习，做到心中有数，否则会影响发挥，再做一遍以前的错题是十分必要的，据说有一个同学平时只有一百零几，离高考只有一个月，把以前错题从头做一遍，最后他数学居然得了147分。2。要重视基础，

另外，听老师的话，勤学苦练不可少，成功没有捷径，要乐观，有毅力，要有决心，还要有耐心，学数学是一个很长的过程，你的努力于回报往往不能那么尽如人意的成正比，甚至会有下坡路的趋势，但只要坚持下去，那条成绩线会抬起头来，一定能看到光明。

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老师，你上课给我们时间发问的的时候，可不可以不要只停在一个角落附近教那里的人，这样别地方的有问题问不到。可以改进吗？sorry我不是在批评，提醒你一下罢了><

Understandable! I will always improve my teaching methods. Please raise your hand when I was not around your corner. Thks for your comment about this.

你好,我是高一理4的张振康(坐在刘思皓旁的那位)

我尝试去解小测验范围的那几页的习题,但有不少都很难,请问能在课堂上解一解吗?

我还有一个问题,请问在什么情况下,根号开出来后前面要放’土'(正负)的符号?

谢谢…

我会在班上解一些.

一般都要放±!

teacher,are the equations x=5根号2/2,x=-5根号2/2？and their gradients are无限？{the minor test question)

Hi Man.U,

You gave me the x-coordinates only, how about the y-coordinates?

Your answers are not equations!!!

The gradient of a straight line y=x is 1. Therefore, the straight line perpendicular to y=x must have the gradient=-1!!!!

From here, you have known 1 point (sqrt(5)/2,?) and a gradient. Can you find out the equation of P? Similarly for Q.

so the equation for q is y=-x-5根号2，p is y=x?

I will solve this today (19-Jan,sat.).

Sir,are u online now?if u free, can u teach me some questions on textbook by using window messenger?

Joyce,

My yahoo messenger is “chtanxw@yahoo.com”. I will be online between 8:00 to 9:30pm.

Sir,ur messenger have 2 ppl using the same email address

how come like this? @@

quote==>> (I will solve this today (19-Jan,sat.).

Comment by chtanmaths — January 18, 2008 @ 9:04 pm )

teacher u havent solve it le..

I know! On Sat. I solved other Rev. Papers so Monday is the tentative time to solve it.

老师。pg29 no.13 & 15 题目再说什么哦？

Q13. asked you to find the centre of a circle which passes through the vertices of the given quadrilateral.

Let A be (-1,1), B be (1,3), C be (3,1) and D be (1,-1) all four points are given. They are the vertices of the quadrilateral.

Step 2: find the equation of the line perpendicular and bisected to BC

Step 3: find the equation of the line perpendicular and bisected to DC

(Of course, you can use any other two sides.)

Step 4: having two equation of the lines. You can find the coordinates of intersection of these two lines. (Let say this point is O)

Step 5: This point is the circumcentre of the triangle BCD.

Step 6: Find the length of OA,OB,OC,OD. If OA=OB=OC=OD then these four become the radius of a circle with O as a center! (Proved. Cyclic means the 4 givens points are on the circle)

Q15.

A rectangle must have 4 perpendicular angles and two pair of parallel lines. Given 3 points. you are asked to find the 4th point.

i know tat Q13 mean le. but Q15 i still dont know le. how to find ? the answer is (6,-2) but it is not a rectangle le.

Q15: Let (a,b) be the 4th point. From a sketch graph, you know that(3,4)&(1,3) must parallel to (a,b)&(4,-3). (3,4)&(a,b) parallel to (1,3)&(4,-3).

Solution:

Step 1: gradient of line (3,4)&(1,3) = (4-3)/(3-1)=1/2

gradient of line (1,3)&(4,-3) = (3-(-3))/(1-4)=-2

These two lines are perpendicular to each other.

Step 2: Gradient of (a,b)&(4,-3) line is

=(b+3)/(a-4)

This one times (-2)=-1

OR The gradient is parallel to the 1st line in step 1.

i.e. equal to 1/2

Step 3: (3,4)&(a,b) line and (a,b)&(4,-3) line:

(4-b)/(3-a) x (b+3)/(a-4) = -1

solve two equations in step2 & step3.